열렬히.뛰기

중위수 구간추정

수학 & 통계 > 수리통계2 > 3. 구간추정 > 중위수 구간추정

m : median. P(X \le m) = 1/2.

X_i’s are i.i.d. X_{(i)} = Y_i.

\begin{align*} Z_i &= I(X_i \le m) \sim bernoulli~\bigg({1 \over 2}\bigg) \\[15pt] Z &= Z_1 + \cdots Z_n \sim binominal~\bigg(n,{1 \over 2} \bigg) \end{align*}
\begin{align*} \therefore~ P(Y_1 \le m) &= P(\text{m보다 작은 표본이 1개 이상}) \\[10pt] &= P(Z \ge 1) = 1 - P(Z=0) \\[10pt] &= 1 - \binom{n}{0} \bigg(\dfrac{1}{2}\bigg)^0 \bigg(\dfrac{1}{2}\bigg)^n \\[15pt] &= 1-\bigg(\dfrac{1}{2}\bigg)^n \\[30pt] P(Y_2 \le m) &= P(Z \ge 2) = 1 - P(Z=0) - P(Z=1) \\[10pt] &= 1 - \binom{n}{0} \bigg(\dfrac{1}{2}\bigg)^0 \bigg(\dfrac{1}{2}\bigg)^n - \binom{n}{0} \bigg(\dfrac{1}{2}\bigg)^1 \bigg(\dfrac{1}{2}\bigg)^{n-1} \\[15pt] &= 1-\bigg(\dfrac{1}{2}\bigg)^n -n~\bigg(\dfrac{1}{2}\bigg)^n \\[30pt] P(m \le Y_7) &= 1 - P(Y_7 < m) \\[10pt] &= 1-P(\text{n개 중 m보다 작은 표본 수 : 7개 이상}) \\[10pt] &= 1 - P(Z \le 7) = P(Z < 7) \end{align*}

공식

\begin{align*} P(Y_k < m) & = \sum_{x=k}^{n}~\binom{n}{x} \bigg({1 \over 2}\bigg)^n = P(Z \ge k) \\[20pt] P(Y_k < m) &= \sum_{x=0}^{k-1}~\binom{n}{x} \bigg({1 \over 2}\bigg)^n = P(Z < k) \\[20pt] P(Y_a < m < Y_b) &= \sum_{x=a}^{b-1}~\binom{n}{x} \bigg({1 \over 2}\bigg)^n \end{align*}

예시 1

\begin{align*} &\text{eg. n=5}~~~P(Y_1 < m < Y_5) \\[10pt] &\sum_{i=1}^{5-1}~\binom{n}{x} \bigg({1\over 2}\bigg)^5 = 0.9375 \\[20pt] &\text{median's 93.75\% confidence interval is }[A_1, A_5] \end{align*}

예시 2

\begin{align*} &\text{eg. n=5}~~~P(Y_2 < m < Y_4) \\[10pt] &\sum_{i=2}^{4-1}~\binom{n}{x} \bigg({1\over 2}\bigg)^5 = 0.625 \\[20pt] &\text{median's 62.5\% confidence interval is }[A_2, A_4] \end{align*}